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Home/ Questions/Q 1043711
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T15:42:44+00:00 2026-05-16T15:42:44+00:00

I need to record a user’s name that is using an ASP.NET web service.

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I need to record a user’s name that is using an ASP.NET web service. To do this, I created a SoapExtension that captures an incoming Soap envelope and converts it to an XDocument. The problem is I know nothing about LINQ to XML and the examples I’ve reviewed don’t quite seem to work with the SOAP envelope.

The SOAP message looks like this:

 <?xml version="1.0" encoding="utf-8"?>
 <soap:Envelope xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:wsa="http://schemas.xmlsoap.org/ws/2004/08/addressing" xmlns:wsse="http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-wssecurity-secext-1.0.xsd" xmlns:wsu="http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-wssecurity-utility-1.0.xsd">
   <soap:Header>
     <wsa:Action>http://www.company.net/2009/09/17/wriapp/GetConfigInfo</wsa:Action>
     <wsa:MessageID>urn:uuid:da599d3d-1df5-4460-8987-8ccd75b87cfe</wsa:MessageID>
     <wsa:ReplyTo><wsa:Address>http://schemas.xmlsoap.org/ws/2004/08/addressing/role/anonymous</wsa:Address></wsa:ReplyTo>
     <wsa:To>urn:Company:Wri:Tracking:1.0</wsa:To>
     <wsse:Security soap:mustUnderstand="1">
       <wsu:Timestamp wsu:Id="Timestamp-efb2ad77-7822-43d9-86d6-0cbfbf0ed262">
           <wsu:Created>2010-09-07T13:31:20Z</wsu:Created>
           <wsu:Expires>2010-09-07T13:36:20Z</wsu:Expires>
       </wsu:Timestamp>
       <wsse:UsernameToken xmlns:wsu="http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-wssecurity-utility-1.0.xsd" wsu:Id="SecurityToken-c51f6c78-555b-420c-ba79-402d75f24d5e">
         <wsse:Username>user@mycompany.net</wsse:Username>
         <wsse:Password Type="http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-username-token-profile-1.0#PasswordText">password1</wsse:Password>
         <wsse:Nonce>xO+f8fJgh8zzxPi6JJMUag==</wsse:Nonce>
         <wsu:Created>2010-09-07T13:31:20Z</wsu:Created>
       </wsse:UsernameToken>
     </wsse:Security>
   </soap:Header>
   <soap:Body>
     <GetConfigInfo xmlns="http://www.company.net/2009/09/17/wriapp" />
   </soap:Body>
 </soap:Envelope>

All I need is the contents of the Username element.

I tried this…

 var xdoc = XDocument.Parse(xml, LoadOptions.None);
 var userName = from item in xdoc.Descendants("UsernameToken")
                select new
                {
                    UserName = item.Element("UserName")
                };

… but get no results.

When I tried using “wsse:UsernameToken” and “wsse:Username” I get an exception which says that the colon is not legal.

Any tips on how to get this information?

(I know I can probably just regex the name, but if I need to grab other data at some future point then it will be more efficient this way, I think.)

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-16T15:42:45+00:00Added an answer on May 16, 2026 at 3:42 pm

    The part in front of the colon is a namespace, knowing this I found this answer from a similar question.

    Linq to XML with Namespace

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