Question

I need to replace [link]0[/link] with <a href=...

Now, the links are saved in an array links and the number inside [link][/link] is the pointer to links index.

I am trying to do next:

txt.replace( /\[link\](\d+)\[\/link\]/ , "<a href='" + links[ THE_INDEX ][ 0 ] + "' target='_blank'>" + ( links[ THE_INDEX ][ 1 ] || links[ THE_INDEX ][ 0 ] ) + "</a>" );

but I don’t know, how to pass the saved value. Could you help me solve it?

P.S. I know I could make loop and use the exec() to save value and pass it, but I want to know, is it possible to do it like I sayd above.

For a more simple example of expectation

my_array = [ "data1", "data2", "data3" ];

"xxx1xxx".replace( /xxx(\d+)xxx/, "my_data=" + my_array[ THE_MATCH ] ); // should be "my_data=data1"
"xxx3xxx".replace( /xxx(\d+)xxx/, "my_data=" + my_array[ THE_MATCH ] ); // should be "my_data=data3"

Where THE_MATCH is taken from the regex match.

Answer 1

Found the solution:

function replacer(str, p1, p2 ){
    return "<a href='" + links[ p1 ] + "'></a>"
}
var newString = "XXzzzz".replace(/(X*)(z*)/, replacer)

While the values passed to replacer() as p1, p2 are the matched values.
The amount of p arguments in replacer() needs to be as the amount of matched values.