Question

I need to represent the time in ("%m/%d/%Y %H:%M:%S") format from the float value I am getting in the form of time.time().

I already have a value that is in the form of time.time(). For example I already have a value I am getting every .3 seconds from a device which is say, 1332449493.0, …., I would then like to convert 1332449493.0 to a strftime format.

EX:
time.strftime(“%m/%d/%Y %H:%M:%S”, 1332449493.0) will throw a TypeError because strf requires a 9-item tuple and not a float.

Answer 1

time.strftime("%m/%d/%Y %H:%M:%S", time.localtime(1332449493.0))

does the job.