Question

I need to run a batch file that goes through 700+ files in a directory and executes them one after another….but with a 3 minute delay. All the files have the same extension, but different file names. So it would execute the first file…..sleep for 3 minutes….then run the next file in the directory.

Thanks

Answer 1

Just use a normal loop and use timeout to wait:

for %%x in (*.extension) do (
  start %%x
  timeout /t 180 /nobreak >nul
)