Question

I need to select transactions with cash payment and same date but only for those transactions
which have only one payment ( so num 14 should be omitted from resultset )
So correct result is 12 and 13 only.

    Table2                          Table1
num  | date | data | total       num | payment | date
12      xy     abc    2.5        12      cash     xy
13      xy     cbc    2.1        13      cash     xy
14      xy     acc    2.3        14      visa     xy
19      xy     def    2.0        14      cash     xy
27      xy     fgh    1.3        19      visa     xy
                                 27       mc      xy  

Something like this gives num 14 in result-set but 14 should be omitted.

SELECT num, data 
FROM Table2
WHERE num IN
(
SELECT num  FROM `Table1`
WHERE payment = 'cash'
GROUP BY `num`
HAVING ( COUNT(`num`) = 1  )
)        

To sumarize correct answer (by tombom ):

 SELECT t2.num, t2.data 
 FROM Table1 as t1
 INNER JOIN Table2 as t2 ON t1.num = t2.num
 AND t1.date = 'xy'  
 GROUP BY t1.num
 HAVING GROUP_CONCAT(t1.payment) = 'cash'

Thanks!

Answer 1

I’m sorry, I totally misunderstood your question. Here’s how it works:

SELECT 
*
FROM
Table1 t1
INNER JOIN Table2 t2 ON t1.num = t2.num AND t1.date = t2.date 
GROUP BY t1.num
HAVING  GROUP_CONCAT(t1.payment) = 'cash'