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Home/ Questions/Q 9195873
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T21:43:30+00:00 2026-06-17T21:43:30+00:00

I need to send a PNG to a server. One very simple solution would

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I need to send a PNG to a server. One very simple solution would be to create a Bitmap and convert it to a byte[] with the following code:

final Bitmap bitmap = BitmapFactory.decodeResource(res, R.drawable.some_image);
final ByteArrayOutputStream os = new ByteArrayOutputStream();
bitmap.compress(CompressFormat.PNG, 100, os);
final byte[] data = os.toByteArray();

Since I want to save time and memory I would like to achieve this without the need of creating a Bitmap.

One idea would be to access the Drawable as a File but I don’t know how to get the correct path.

Any ideas?

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  1. Editorial Team
    Editorial Team
    2026-06-17T21:43:31+00:00Added an answer on June 17, 2026 at 9:43 pm

    harism gave me the final hint: use one of the Resoureces.openRawResource methods.

    Here is my final solution:

    private byte[] fetchImageData(Resources res) throws IOException {
        final AssetFileDescriptor raw = res.openRawResourceFd(R.drawable.some_image);
        final FileInputStream is = raw.createInputStream();
    
        // there are plenty of libraries around to achieve this with just one line...
        final ByteArrayOutputStream buffer = new ByteArrayOutputStream();
    
        int nRead;
        final byte[] data = new byte[16384];
    
        while ((nRead = is.read(data, 0, data.length)) != -1) {
            buffer.write(data, 0, nRead);
        }
    
        buffer.flush();
    
        return buffer.toByteArray();
    }
    

    In my case I had an PNG of 250×200 px and a file size of 42046 Byte. The Bitmap approach needs around 500ms and the raw approach 3ms.

    Hope someone can use this solution.

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