Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Please briefly explain why you feel this question should be reported.
Please briefly explain why you feel this answer should be reported.
Please briefly explain why you feel this user should be reported.
I need to send a variable to another script (BASH) and uset after in this first script. The code goes something like this:
read var
source myscipt.sh $var
echo $var
The problem is that if y put spaces when entering $var after sending it to myscript.sh I only have the first one.
NOTE: In myscript.sh I only use $1 does this have something to do with the problem?
Thanx!!!
You need to use quotes. Thus var will be considered as only one parameter, even if it contains spaces.