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Home/ Questions/Q 8514155
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T04:47:02+00:00 2026-06-11T04:47:02+00:00

I need to sort 2-dimensional array in descending order keeping original indexes: $arr =

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I need to sort 2-dimensional array in descending order keeping original indexes:

$arr = array();

for ($i=0; $i<5; $i++) {
    $arr[] = array(rand(0,5), rand(10,100));
}

The result must be something like this:

[0] => array(5, 100)
[1] => array(5, 90)
[2] => array(5, 35)
[3] => array(4, 10)
[4] => array(3, 15)

So, firstly, the array is sorted with respect to the 1st column, and, secondly it is sorted with respect to the 2nd column.

The function arsort works with vectors, if I understand it correctly.

How can I solve this task?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-11T04:47:04+00:00Added an answer on June 11, 2026 at 4:47 am

    see http://docs.php.net/uasort

    e.g.

    <?php
    $arr = array(
        'A'=>array(5, 100),
        'B'=>array(4, 10),
        'C'=>array(5, 35),
        'D'=>array(3, 15),
        'E'=>array(5, 90)
    );
    
    uasort($arr, function($a, $b) {
        if ( $a[0] < $b[0] ) return 1;
        else if ( $a[0] > $b[0] ) return -1;
        else if ( $a[1] < $b[1] ) return 1;
        else if ( $a[1] > $b[1] ) return -1;
        else return 0;
    });
    
    foreach($arr as $k=>$v) {
        echo $k,'=', join(', ', $v), "\n";
    }
    

    prints

    A=5, 100
    E=5, 90
    C=5, 35
    B=4, 10
    D=3, 15
    
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