I need to sort 20+ arrays, already on the GPU, each of the same length, by the same keys. I can not use sort_by_key() directly since it sorts the keys as well (making them useless to sort the next array). Here is what I tried instead:
thrust::device_vector<int> indices(N);
thrust::sequence(indices.begin(),indices.end());
thrust::sort_by_key(keys.begin(),keys.end(),indices.begin());
thrust::gather(indices.begin(),indices.end(),a_01,a_01);
thrust::gather(indices.begin(),indices.end(),a_02,a_02);
...
thrust::gather(indices.begin(),indices.end(),a_20,a_20);
This does not seem to work since gather() expects a different array for the output than for the input, i.e. this works:
thrust::gather(indices.begin(),indices.end(),a_01,o_01);
...
However, I would prefer to not allocate 20+ extra arrays for this task. I know that there is a solution using a thrust::tuple, thrust::zip_iterator and thrust::sort_by_keys(), similiar to here. However, I can only combine up to 10 arrays in a tuple, s.t. I would need to duplicate the key vector again. How would you tackle this task?
Well, you really only need to allocate one extra array if you are OK with manipulating pointers to
device_vectorinstead:Or something like that should work anyway. You would need to fix it so the temp device vector is not automatically deallocated when it goes out of scope — I suggest allocating the CUDA device pointers using cudaMalloc and then wrapping them with device_ptr instead of using automatic device_vectors.