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Home/ Questions/Q 6175593
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T23:57:05+00:00 2026-05-23T23:57:05+00:00

I need to sort an array of age groups. The challenge is that any

  • 0

I need to sort an array of age groups. The challenge is that any age groups less than 10 sort higher than those 10-19 when using the standard NSArray localizedCaseInsensitiveCompare

Specifically, here’s an example of what my unsorted array might look like:

(
“17-18”,
“13-14”,
“8 and Under”,
“Women”,
“Men”,
“15-16”
)

After sorting, I would want it to look like this:

(
“8 and Under”,
“13-14”,
“15-16”,
“17-18”,
“Men”,
“Women”
)

But it ends up looking something like this:

(
“13-14”,
“15-16”,
“17-18”,
“8 and Under”,
“Men”,
“Women”
)

This is using the following code:

    NSArray *sortedAgeArray = [ageArray sortedArrayUsingSelector:@selector(localizedCaseInsensitiveCompare:)];

I like that “Men” and “Women” gets put on the end, that’s what I want. But is there a clever/efficient way to deal with the ages that are less than 10? Reformatting my data to include leading zeroes is not an option.

I know I can write a custom sorting function, but I’m trying to avoid having to do so.

Thanks!

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  1. Editorial Team
    Editorial Team
    2026-05-23T23:57:06+00:00Added an answer on May 23, 2026 at 11:57 pm

    You could use localizedStandardCompare: instead of localizedCaseInsensitiveCompare:. This is what the Finder uses and it’s smart enough to evaluate “8” as smaller than “13” without leading zeros.

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