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Home/ Questions/Q 9196493
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T21:51:43+00:00 2026-06-17T21:51:43+00:00

I need to split a java string into an array of words. Let’s say

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I need to split a java string into an array of words. Let’s say the string is:

"Hi!! I need to split this string, into a serie's of words?!"

At the moment I’m tried using this String[] strs = str.split("(?!\\w)") however it keeps symbols such as ! in the array and it also keeps strings like “Hi!” in the array as well. The string I am splitting will always be lowercase. What I would like is for an array to be produced that looks like:
{"hi", "i", "need", "to", "split", "this", "string", "into", "a", "serie's", "of", "words"} – Note the apostrophe is kept.

How could I change my regex to not include the symbols in the array?

Apologies, I would define a word as a sequence of alphanumeric characters only but with the ‘ character inclusive if it is in the above context such as “it’s”, not if it is used to a quote a word such as “‘its'”. Also, in this context “hi,” or “hi-person” are not words but “hi” and “person” are. I hope that clarifies the question.

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  1. Editorial Team
    Editorial Team
    2026-06-17T21:51:44+00:00Added an answer on June 17, 2026 at 9:51 pm

    You can remove all ?! symbols and then split into words

    str = str.replaceAll("[!?,]", "");
    String[] words = str.split("\\s+");
    

    Result:

    Hi, I, need, to, split, this, string, into, a, serie's, of, words

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