Question

I need to split first column delimited by ‘#’ into two columns. My data is in following format.

1#b,a
2#b,a
5#c,d

Required Output:

1,b,a
2,b,a
5,c,d

Other columns can have # in their values so I want to apply regex only on first column.

Thanks
Jitendra

Answer 1

A file (file.orig) contains this:

1#b,a #
2#b,a #
5#c,d #

Use sed:

sed 's/#/,/1' file.orig > file.new

Output (cat file.new):

1,b,a #
2,b,a #
5,c,d #