Question

I need to sum a group for my query. Something like:

SELECT customer_id, SUM(weekly) FROM earnings GROUP BY customer_id

The above works, but I need something a bit more complex, and my query is like this:

SELECT
    (SELECT SUM(weekly) FROM earnings) + 
    (SELECT SUM(day_earnings) FROM earnings) / .75

The above makes the sum of all the earnings, weekly and daily, but I need to group them by customer_id like in the first example. How do I achieve this?

Answer 1

According to the order of operations in your attempt above, it’s the SUM(day_earnings) only that’s divided by .75. If it should be the weekly & day_earnings sums together, then put parentheses around them as (SUM(weekly) + SUM(day_earnings)) / 0.75 AS earnings.

SELECT 
  customer_id,
  customer_name,
  SUM(weekly) + SUM(day_earnings) / 0.75 AS earnings
FROM earnings JOIN customers ON earnings.customer_id = customers.customer_id
GROUP BY customer_id, customer_name