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Home/ Questions/Q 7619143
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T03:36:28+00:00 2026-05-31T03:36:28+00:00

I need to track my current location in a data buffer (which will be

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I need to track my current location in a data buffer (which will be used as a packet), so I am using two variables, bufferLoc and dataBuffer.

char dataBuffer[8192];
char** bufferLoc;

I am pointing to the starting location of dataBuffer with bufferLoc. But incrementing bufferLoc does not affect its physical address in memory.

bufferLoc = (char**)&dataBuffer;

cout << &bufferLoc << endl;

bufferLoc++;

cout << &bufferLoc << endl;

These two prints will output the same location. Does my error have to do with type casting, with bufferLoc itself, or something completely different?

Thanks for your help.

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  1. Editorial Team
    Editorial Team
    2026-05-31T03:36:29+00:00Added an answer on May 31, 2026 at 3:36 am

    If your intention is to scan through dataBuffer one byte at a time, then the second variable should be a pointer, not a pointer to a pointer.

    char* bufferLoc;
    

    then print it out without the ampersand:

    cout << (unsigned int *)bufferLoc << endl;
    

    note that cout will try to print your variable as text unless you cast to an unsigned int*

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