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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T02:03:43+00:00 2026-05-26T02:03:43+00:00

I need to transform an xml to some custom xml format. In the new

  • 0

I need to transform an xml to some custom xml format.

In the new format i would have many sections node and for each node i am creating a unique id using:

<xsl:attribute name="identifier">
                <xsl:variable name="uid" select="util:randomUUID()"/>A<xsl:value-of select="util:toString($uid)"/>
</xsl:attribute>

I need a way to store all of these Ids in a list or array so that i can refer it back from some other template and use them in for-each loop.

Is there a way to do this with xsl?

Thanks for any help

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T02:03:44+00:00Added an answer on May 26, 2026 at 2:03 am

    Have these globally declared:

    <xsl:variable name="vrtfRandList">
     <xsl:for-each select="yourNodeSet">
      <rand><xsl:value-of select="util:randomUUID()"/></rand>
     </xsl:for-each>
    </xsl:variable>
    
    <xsl:variable name="vRandlist" select="ext:node-set($vrtfRandList)/*"/>
    

    Then later use:

    $vRandlist[$k]
    

    Using XSLT 2.0:

    <xsl:variable name="vRandlist" as="xs:integer*"
         select="for $i in 1 to count(yourNodeSet)
                  return 
                     util:randomUUID()
                "/>
    
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