Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 7063115
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 28, 20262026-05-28T04:40:31+00:00 2026-05-28T04:40:31+00:00

I need to update a section on my site frequently using ajax, jquery, and

  • 0

I need to update a section on my site frequently using ajax, jquery, and php.

When the page first loads, it calls a javascript function that displays the content of that section. Then using json I check for updates and if there are results, calls the same function to display it.

Now inside the ajax content there are links like

<a href="news.php?id" class="ajaxpopup">title</a>

to call fancybox but instead of opening a popup, it opens the page directly.
If the link to call fancybox is not inside an ajax content it displays properly.
I know that there are some people with the same problem but the answers are for divs with specific id.
How can I set it globally. I mean to work on links with class=”ajaxpopup”?

this is my function to call the content

$(document).ready(function() {
  $(".ajaxpopup").fancybox({
    'overlayColor'      : '#000000', 
    'centerOnScroll'    : true,
    'transitionIn'      : 'none',
    'transitionOut'     : 'none',
    'modal'             : true
  }); 
});

function update(page,value)    {
  var data = 'id='+value;
  $.ajax({
    url: page,
    type: "POST",       
    data: data,     
    cache: false,
    success: function (html) {  
      $('#updates').html(html);   
      $('#updates').fadeIn(200);      
    }       
  });
}

then the divs

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-28T04:40:32+00:00Added an answer on May 28, 2026 at 4:40 am

    After loading the dynamic content, bind the fancy box again

     div.load("myserverpage.aspx?mode=popularmodels", { symbol: $("#txtSymbol").val() }, function() {
                    $(this).fadeIn(100);
    
                    $(".ajaxpopup").fancybox({
                        'scrolling': 'no',
                        'titleShow': true,
                        'titlePosition': 'over',
                        'onClosed': function () {
                            $("#login_error").hide();
                        }
                    });
                });
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I need to update this code: radar_layer.getTileUrl=function(tile,zoom) { var llp = new GPoint(tile.x*256,(tile.y+1)*256); var
I need to update a combobox with a new value so it changes the
I need to update a record in a database with the following fields [ID]
I need to update a group of cells by inserting the same two characters
I need to update the comments field in a table for a large list
I need to update a field (which is currently empty) based on a match
I need to update an existing SharePoint content type by adding a new field
I need to update the primary key for a record but it's also the
I need to update a record in the datastore, but instead of updated record
I need to update jquery1.3.2 to jquery1.4 (in Asp.net MVC). Please can anyone tell

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.