Question

i need to use this query to return records with the most recent NoteDate, instead of returning duplicate records showing each note date. i thought that putting the ‘MAX’ in front of t.notedate would get rid of the duplicate records but they still show up.

SELECT    c.ContactId,  MAX(t.notedate),c.Source, c.FirstName, c.LastName,  c.Phone1, crCallResultCode, crTotalCallCount

FROM         dbo.t_Contact c inner join t_notes t on c.contactid=t.contactid

WHERE     

(c.Source IN ('Cabo10MC', 'BOWN10')) AND 
 (c.crCallResultCode NOT IN ('V02', 'S01', 'CNC', 'R99','U01', 'U02', 'U03')) AND 
 (DATEDIFF(ww, crNextCallDateTime, GETDATE()) = 0)OR (crNextCallDateTime = '1/1/1900')AND 
 (c.Phone1 NOT IN
                          (SELECT     phone
                            FROM          lema.dbo.tswlivetours
                            WHERE      TourDate > getdate() AND TourStatus IN ('showed')))

group by c.ContactId,  c.Source, c.FirstName, c.LastName,  c.Phone1, crCallResultCode, crTotalCallCount,t.notedate

Answer 1

Remove t.notedate from your group by clause.

...group by c.ContactId,  c.Source, c.FirstName, c.LastName,  c.Phone1, crCallResultCode, crTotalCallCount