Question

I need to write a function that read from a file and put every some lines as one cell in a list.
I need to copy the lines between 1 to 2 and from 2 to the end and put each of them in different cell in the list, without the lines that contains the number and empty lines.
I dont have an idea how make it work.

the file:

; 1

####
# .#
#  ###
#*@  #
#  $ #
#  ###
####

; 2

######
#    #
# #@ #
# $* #
# .* #
#    #
######

my code:

def loader(filename):
    levels=[[]]
    f=open(filename, "r")
    x=[]
    for line in f:
        if ";" not in line:
            x.append(line)
        else:
            levels.append(x)
    f.close()
    return levels

output:
cell 1:

####
# .#
#  ###
#*@  #
#  $ #
#  ###
####

cell 2:

######
#    #
# #@ #
# $* #
# .* #
#    #
######

Answer 1

Final best solution:

If you use re, you can find anything from

; 1

to

;    2

Here’s the code:

import re
levels = [x[2:].strip() for x in re.split(';\s*\d', open(filename).read()) if x != '']

older: (compensates for numbers, and gets rid of blank lines completely)

levels = [x[2:].strip() for x in open(filename).read().split(';') if x != '']

OR

levels = [x[1:].strip() for x in open(filename).read().split('; ') if x.strip() != '']

To print the output:

for level in levels:
    print level

Or individually:

print levels[0]
print levels[1]