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Home/ Questions/Q 8421655
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Editorial Team
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Editorial Team
Asked: June 10, 20262026-06-10T03:12:28+00:00 2026-06-10T03:12:28+00:00

I need to write a function which finds the possible fixed length combinations of

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I need to write a function which finds the possible fixed length combinations of a string. The need is that not all combis are required. For example, if the string is “abcde”, and we need combis of length 3, then the function must return the following:

abc
abd
abe
acd
ace
ade
bcd
bde
bce
cde

and none else. I have been trying for it using recursion but things have not worked out as expected. I have also seen some similar questions but could not get much out of them. Algorithm or code(C, C++, Java), any help is welcome. Thanks.!

Note: The combinations need to be ordered. That is, the characters should follow the same order as in the input string.

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  1. Editorial Team
    Editorial Team
    2026-06-10T03:12:29+00:00Added an answer on June 10, 2026 at 3:12 am

    I expect it’s possible to do better, but this is what I could come up with quickly.

    I used a List to preserve order, and had to avoid duplicates awkwardly. Using a Set instead would allow us to skip the result.contains(s) check, but a better algorithm might avoid the duplicates in a cleaner way.

    private static List<String> substrings(int i, String input) {
        List<String> result = new ArrayList<String>();
        if (i == 0)
            return result;
    
        String first = input.substring(0, i);
        result.add(first);
    
        if (input.length() == i) {
            return result;
        }
    
        // Recursively find substrings of next smaller length not including the first character
        List<String> tails = substrings(i-1, input.substring(1));
    
        // Append first char to each result of the recursive call.
        for (String sub: tails) {
            String s = input.substring(0, 1) + sub;
            if (!(result.contains(s)))
                result.add(s);
        }
    
        // Add all substring of current length not including first character
        result.addAll(substrings(i, input.substring(1)));
        return result;
    }
    
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