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Home/ Questions/Q 8958225
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T15:09:48+00:00 2026-06-15T15:09:48+00:00

I need to write a Haskell program that will generate a diamond output recursively.

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I need to write a Haskell program that will generate a diamond output recursively.
Here is some sample output for given input

input : 1
output :

 *
* *
 *

input : 2
output :

    *
   * *
    *
 *     *
* *   * *
 *     *
    *
   * *
    *

input : 3
output :

             *             
            * *             
             *              
          *     *           
         * *   * *          
          *     *           
             *              
            * *             
             *              

    *                 *    
   * *               * *   
    *                 *    
 *     *           *     * 
* *   * *         * *   * *
 *     *           *     * 
    *                 *    
   * *               * *   
    *                 *    
             *             
            * *             
             *              
          *     *           
         * *   * *          
          *     *           
             *              
            * *             
             *     

I wrote following functions:

next 0 = [1,0,1]
next n = map (+3^n) (next (n-1)) ++ next (n-1) ++ map (+3^n) (next (n-1))
lpad n = map (++"*") (zipWith ($) (map (take)(next (n-1))) ((repeat(repeat ' '))))
pretty n = putStrLn $ intercalate "\n" $ lpad n

which gives following outputs:

pretty 1

 *
*
 *

pretty 2

    *
   *
    *
 *
*
 *
    *
   *
    *

Can anyone help me with the remaining halves? Thanks in advance.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-15T15:09:50+00:00Added an answer on June 15, 2026 at 3:09 pm

    For n==0, next n describes the whole picture up to mirroring. This is not the case anymore for greater n. So, in a first step, we change the next function to output a symmetric picture:

    mmap = map . map
    
    next :: Int -> [[Int]]
    next 0 = [[1],[0,2],[1]]
    next n = sn ++ map (\a -> a ++ map (+2*3^n) a) nn ++ sn
      where
        nn = next (n - 1)
        sn = mmap (+3^n) nn
    

    Now, next n describes the positions of all stars. To print them, we first compute the relative distances.

    diffs :: [Int] -> [Int]
    diffs (x:xs) = x: diffs' x (xs)
      where
        diffs' x (y:ys) = y - x - 1 : diffs' y ys
        diffs' _ [] = []
    diffs [] = []
    
    lpad :: Int -> [[Char]]
    lpad = map (concatMap $ \n -> replicate n ' ' ++ "*") . map diffs . next'
    

    Applied to one line, diffs returns the list of the number of spaces we need to put before each star and lpad generates the picture from that. Print it as before:

    pretty :: Int -> IO ()
    pretty n = putStrLn $ unlines $ lpad n
    
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