Question

I need to Write a Unix shell script that accepts two or more arguments, a file mode, a command and an optional list of parameters and performs the given command with the optional parameters on all files with that given mode.

For example, mycode 644 ls -l should perform the command ls -l on all files in the current directory that have mode 644.

I use this code to change the file permission to numeric mode

#!/bin/sh
 mode=$1
 #it adds the numeric permission to the beginning of the line
 ls -l |awk '{k=0;for(i=0;i<=8;i++)k+=((substr($1,i+2,1)~/[rwx]/) \
         *2^(8-i));if(k)printf("%0o ",k);print }'
 .....
 shift $1
 $*

but I dont know how to ask the code to list only files with same permissions. how can I ask the code to do it?

Answer 1

Use the find command for this. E.g.

find . -maxdepth 1 -perm 644 -exec ls -ld {} \;