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Home/ Questions/Q 6611043
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T19:55:09+00:00 2026-05-25T19:55:09+00:00

I need to write an interceptor/filter in my spring-jersey application, which will check every

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I need to write an interceptor/filter in my spring-jersey application, which will check every request for session and on success it will pass a code to respective controller. Passing this code is imp, because based on the code controller will decide further action.

Q:
1) Is this possible to write this kind of login filter in Spring? How?
2) Is this possible to pass some code to controller from interceptor? How?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-25T19:55:10+00:00Added an answer on May 25, 2026 at 7:55 pm

    We need to implement ContainerRequestFilter interface for creating Jersey filter. Following is the code sample for intercepting and modifying a request using jersey filter:

    import com.sun.jersey.spi.container.ContainerRequest;
    import com.sun.jersey.spi.container.ContainerRequestFilter;
    import javax.ws.rs.core.MultivaluedMap;
    import org.apache.log4j.Logger;
    
    /**
     *
     * @author arnav
     */
    public class MyAppFilter implements ContainerRequestFilter{
    
    
       public ContainerRequest filter(ContainerRequest request) {
    
          MultivaluedMap<String, String> headers = request.getRequestHeaders();
    
          headers.add("code", "MY_APP_CODE");
          request.setHeaders((InBoundHeaders)headers);
    
          return request;
       }
    }
    

    After adding this class, we need to register this filter for our web application. So now we will add following lines in our web.xml:

    <servlet>
          ..........
          ..........   
          <init-param>
             <param-name>com.sun.jersey.spi.container.ContainerRequestFilters</param-name>
             <param-value>package.MyAppFilter</param-value>
          </init-param> 
    </servlet>
    
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