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Asked: 2026-05-13T11:26:38+00:00

I need to write queries to find out new users and regular users .

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I need to write queries to find out new users and regular users.

new users are the ones whose uuid appeared in last 24 hours (from now minus the time query is fired) in table2 and was not there before.

regular users are the ones whose uuid appeared in last day in table2 and was also there at least once in the last 3 days.

In addition to this only records with id > 10 and ip != 2 are to be considered.

table1 is a temporary table containing dates. I am not able to figure out how to achieve this with help of joins. Please help me.

table2

    +----+---------------------+------+------+
    | id | ts                  | uuid | ip   |
    +----+---------------------+------+------+
    |  1 | 2010-01-10 00:00:00 | uid1 |    5 |
    |  2 | 2010-01-10 00:00:00 | uid2 |   14 |
    |  3 | 2010-01-10 00:00:00 | uid3 |   11 |
    |  4 | 2010-01-11 00:00:00 | uid4 |   16 |
    |  5 | 2010-01-11 00:00:00 | uid5 |    4 |
    |  6 | 2010-01-13 00:00:00 | uid6 |    2 |
    |  7 | 2010-01-10 00:00:00 | uid1 |    1 |
    |  8 | 2010-01-11 00:00:00 | uid2 |   10 |
    |  9 | 2010-01-12 00:00:00 | uid1 |    1 |
    | 10 | 2010-01-13 00:00:00 | uid4 |    1 |
    | 11 | 2010-01-09 21:00:00 | uid1 |    1 |
    | 12 | 2010-01-09 21:30:00 | uid1 |    2 |
    | 13 | 2010-01-10 05:00:00 | uid2 |    3 |
    | 14 | 2010-01-10 12:00:00 | uid1 |    1 |
    | 15 | 2010-01-10 12:00:00 | uid3 |    1 |
    | 16 | 2010-01-10 21:00:01 | uid1 |    7 |
    | 17 | 2010-01-11 01:00:00 | uid2 |   14 |
    | 18 | 2010-01-11 05:00:00 | uid2 |   11 |
    | 19 | 2010-01-11 17:59:00 | uid4 |   13 |
    | 20 | 2010-01-11 06:00:00 | uid5 |   12 |
    | 21 | 2010-01-11 18:01:00 | uid1 |   14 |
    | 22 | 2010-01-12 23:05:00 | uid4 |   17 |
    | 23 | 2010-01-13 12:01:23 | uid6 |   13 |
    +----+---------------------+------+------+
    23 rows in set (0.00 sec)

table1

    +------------+
    | ts         |
    +------------+
    | 2010-01-10 |
    | 2010-01-11 |
    | 2010-01-12 |
    | 2010-01-13 |
    +------------+
    4 rows in set (0.00 sec)

Output in case of new users taken at 18:00

+------------+-------+
| ts         | users |
+------------+-------+
| 2010-01-10 |     3 |
| 2010-01-11 |     2 |
| 2010-01-12 |     0 |
| 2010-01-13 |     1 |
+------------+-------+
4 rows in set (0.00 sec)

MySQL table dump

DROP TABLE IF EXISTS `table1`;
/*!40101 SET @saved_cs_client     = @@character_set_client */;
/*!40101 SET character_set_client = utf8 */;
CREATE TABLE `table1` (
  `ts` date NOT NULL
) ENGINE=MyISAM DEFAULT CHARSET=latin1;
/*!40101 SET character_set_client = @saved_cs_client */;

INSERT INTO `table1` VALUES ('2010-01-10'),('2010-01-11'),('2010-01-12'),('2010-01-13');

DROP TABLE IF EXISTS `table2`;
CREATE TABLE `table2` (
  `id` int(11) NOT NULL AUTO_INCREMENT,
  `ts` datetime DEFAULT NULL,
  `uuid` varchar(20) DEFAULT NULL,
  `ip` int(11) DEFAULT NULL,
  PRIMARY KEY (`id`)
) ENGINE=MyISAM AUTO_INCREMENT=24 DEFAULT CHARSET=latin1;
/*!40101 SET character_set_client = @saved_cs_client */;

INSERT INTO `table2` VALUES (1,'2010-01-10 00:00:00','uid1',5),(2,'2010-01-10 00:00:00','uid2',14),(3,'2010-01-10 00:00:00','uid3',11),(4,'2010-01-11 00:00:00','uid4',16),(5,'2010-01-11 00:00:00','uid5',4),(6,'2010-01-13 00:00:00','uid6',2),(7,'2010-01-10 00:00:00','uid1',1),(8,'2010-01-11 00:00:00','uid2',10),(9,'2010-01-12 00:00:00','uid1',1),(10,'2010-01-13 00:00:00','uid4',1),(11,'2010-01-09 21:00:00','uid1',1),(12,'2010-01-09 21:30:00','uid1',2),(13,'2010-01-10 05:00:00','uid2',3),(14,'2010-01-10 12:00:00','uid1',1),(15,'2010-01-10 12:00:00','uid3',1),(16,'2010-01-10 21:00:01','uid1',7),(17,'2010-01-11 01:00:00','uid2',14),(18,'2010-01-11 05:00:00','uid2',11),(19,'2010-01-11 17:59:00','uid4',13),(20,'2010-01-11 06:00:00','uid5',12),(21,'2010-01-11 18:01:00','uid1',14),(22,'2010-01-12 23:05:00','uid4',17),(23,'2010-01-13 12:01:23','uid6',13);
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1 Answer

  1. Editorial Team

    You can join the table on itself to search for entries for the same user that are more than a day old. When there’s no day-old match, fields in the left joined table will be NULL.

    For example:

    select     
  YEAR(cur.ts) as year
, MONTH(cur.ts) as month
, DAY(cur.ts) as day
, case when old.uuid is null then 1 else 0 end as IsNewUser
, count(distinct cur.uuid) as Users
from       table2 cur
left join  table2 old
on         cur.uuid = old.uuid
           and old.ip <> 2
           and old.id > 10
           and cur.ts - old.ts > 1
where      cur.ip <> 2
           and cur.id > 10
group by   year, month, day, IsNewUser
order by   year, month, day, IsNewUser
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