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Asked: 2026-06-03T08:33:21+00:00

I need xslt to transform, My Xml is as below <OrderReferences> <OrderRef> <OrderRef>OrderRef1</OrderRef> <Type>ERP</Type>

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I need xslt to transform, My Xml is as below

 <OrderReferences>
            <OrderRef>
              <OrderRef>OrderRef1</OrderRef>
              <Type>ERP</Type>
            </OrderRef>
            <OrderRef>
              <OrderRef>OrderRef2</OrderRef>
              <Type>CUSTOMER</Type>
            </OrderRef>
            <OrderRef>
              <OrderRef>OrderRef3</OrderRef>
              <Type>EXT</Type>
            </OrderRef>
          </OrderReferences>

My Output from this should be 

<OrderReference> (OrderReference for ERP should appear here) </OrderReference>
<OrderReferenceCustomer> (CustomerReference for Customer should appear here) </OrderReferenceCustomer>
<OrderReferenceExternal> (ExtReference for EXT should appear here) </OrderReferenceExternal>

Let me know if this is achievable. XSLT 1.0 version preferrable as i want this for .Net. Thanks.

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1 Answer

  1. Editorial Team

    This short and simple transformation:

    <xsl:stylesheet version="1.0"
 xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
 <xsl:output omit-xml-declaration="yes" indent="yes"/>
 <xsl:strip-space elements="*"/>

 <xsl:template match="OrderRef[Type='ERP']">
     <OrderReference><xsl:value-of select="OrderRef"/></OrderReference>
 </xsl:template>

 <xsl:template match="OrderRef[Type='CUSTOMER']">
     <OrderReferenceCustomer><xsl:value-of select="OrderRef"/></OrderReferenceCustomer>
 </xsl:template>

 <xsl:template match="OrderRef[Type='EXT']">
     <OrderReferenceExternal><xsl:value-of select="OrderRef"/></OrderReferenceExternal>
 </xsl:template>
</xsl:stylesheet>

    when applied on the provided XML document:

    <OrderReferences>
    <OrderRef>
        <OrderRef>OrderRef1</OrderRef>
        <Type>ERP</Type>
    </OrderRef>
    <OrderRef>
        <OrderRef>OrderRef2</OrderRef>
        <Type>CUSTOMER</Type>
    </OrderRef>
    <OrderRef>
        <OrderRef>OrderRef3</OrderRef>
        <Type>EXT</Type>
    </OrderRef>
</OrderReferences>

    produces the exact wanted, correct result (unlike the currently accepted answer):

    <OrderReference>OrderRef1</OrderReference>
<OrderReferenceCustomer>OrderRef2</OrderReferenceCustomer>
<OrderReferenceExternal>OrderRef3</OrderReferenceExternal>
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