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Home/ Questions/Q 8071605
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Editorial Team
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Editorial Team
Asked: June 5, 20262026-06-05T13:44:28+00:00 2026-06-05T13:44:28+00:00

I need your help to solve a silly problem. I have 2 tables in

  • 0

I need your help to solve a silly problem.
I have 2 tables in my database (contents and categories).

I have populated my MySQL table called “categories”, and now I want to see in a form the old category stored in the database while I modify it to a new one.

Unfortunately what I wrote shows only the list of the categories get from the database table.

<select name="PostedCat">
    <?php 

    $query_category = "SELECT * FROM categ";
    $result_category =  mysql_query($query_categ) or die (mysql_error());


    while($categ = mysql_fetch_assoc($result_category)){        
    ?>
        <option value="<?php echo $categ['cat_title']; ?>" ><?php echo $categ['cat_title']; ?></option>
    <?php
    }                       
    ?>
</select>

With this code I can see the categories stored in the database, but how can I get the “old” selected one? The stored one?

Hope in some help, but I’m blind at the moment.

Thank you in advance.

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  1. Editorial Team
    Editorial Team
    2026-06-05T13:44:29+00:00Added an answer on June 5, 2026 at 1:44 pm

    Assuming your old category is in $oldcat, just do

    $query_category = "SELECT * FROM categ";
    $result_category =  mysql_query($query_categ) or die (mysql_error());
    
    
    while($categ = mysql_fetch_assoc($result_category)){        
    ?>
        <option value="<?php echo $categ['cat_title']; if ($categ['cat_title']==$oldcat) echo '" selected="true'; ?>" ><?php echo $categ['cat_title']; ?></option>
    <?php
    }                       
    ?>
    

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