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Asked: May 11, 20262026-05-11T02:23:23+00:00 2026-05-11T02:23:23+00:00

I never actually thought I’d run into speed-issues with python, but I have. I’m

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I never actually thought I’d run into speed-issues with python, but I have. I’m trying to compare really big lists of dictionaries to each other based on the dictionary values. I compare two lists, with the first like so

biglist1=[{'transaction':'somevalue', 'id':'somevalue', 'date':'somevalue' ...}, {'transactio':'somevalue', 'id':'somevalue', 'date':'somevalue' ...}, ...] 

With ‘somevalue’ standing for a user-generated string, int or decimal. Now, the second list is pretty similar, except the id-values are always empty, as they have not been assigned yet.

biglist2=[{'transaction':'somevalue', 'id':'', 'date':'somevalue' ...}, {'transactio':'somevalue', 'id':'', 'date':'somevalue' ...}, ...] 

So I want to get a list of the dictionaries in biglist2 that match the dictionaries in biglist1 for all other keys except id.

I’ve been doing

for item in biglist2:     for transaction in biglist1:        if item['transaction'] == transaction['transaction']:           list_transactionnamematches.append(transaction)  for item in biglist2:     for transaction in list_transactionnamematches:        if item['date'] == transaction['date']:           list_transactionnamematches.append(transaction) 

… and so on, not comparing id values, until I get a final list of matches. Since the lists can be really big (around 3000+ items each), this takes quite some time for python to loop through.

I’m guessing this isn’t really how this kind of comparison should be done. Any ideas?

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  1. 2026-05-11T02:23:23+00:00Added an answer on May 11, 2026 at 2:23 am

    Index on the fields you want to use for lookup. O(n+m)

    matches = [] biglist1_indexed = {}  for item in biglist1:     biglist1_indexed[(item['transaction'], item['date'])] = item  for item in biglist2:     if (item['transaction'], item['date']) in biglist1_indexed:         matches.append(item) 

    This is probably thousands of times faster than what you’re doing now.

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