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Home/ Questions/Q 4066164
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T16:06:01+00:00 2026-05-20T16:06:01+00:00

I new to parsing JSON – up until this point, I’ve been purely XML.

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I new to parsing JSON – up until this point, I’ve been purely XML. Anyways, I am using JSON (Java ME) to parse something with the following structure:

{"name" : "JACK","name" : "JILL","name" : "JOHN","name" : "JENNY","name" : "JAMES","name" : "JIM"}

Here is my code:

    try {
        JSONObject json = new JSONObject(response);
        JSONArray jsonArray = outer.getJSONArray("name");
        System.out.println("ARRAY SIZE:"
                + jsonArray.length());
    } catch (JSONException ex) {
    }

My problem is that I cannot even get the println(“ARRAY SIZE:”…) statement to output at all in my Eclipse console. The only time that I am getting any sort of output is if I use the following code:

try {
        JSONObject json = new JSONObject(response);
        System.out.println("OUTPUT:"
                + json.getString("name"));
    } catch (JSONException ex) {
    }

…That seems to give me only the last element. Is there a reason why I cannot get the JSONArray to work? Is it because the JSON contains no “outer” key?

I’d appreciate any help. Thanks!

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  1. Editorial Team
    Editorial Team
    2026-05-20T16:06:02+00:00Added an answer on May 20, 2026 at 4:06 pm

    The key must be unique. You need to differentiate those “name”‘s by using “Name1”, “Name2”, … etc

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