Home/ Questions/Q 6594353
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Asked: 2026-05-25T17:48:00+00:00

I normalized a vector and length of it should be 1. But the result

  • 0

I normalized a vector and length of it should be 1. But the result of length method is 0.99999982

I don’t know it’s right or wrong. But if I print it out, the result is 1. Not 0.99999982( printed by cout )

But how std::cout knows it’s 1? [This is my first question]

And another question is why the result of comparing function is false.

I have a comparing method like below. And lhs is the length of a vector and the rhs is just 1.


return (fabsf(rhs-lhs) <= FLT_EPSILON) ? true : false;

Result of this method is false.

Is length of the normalized vector is already wrong to be considered normalized? or epsilon is too small?

What did I wrong?

Share

Leave an answer

You must login to add an answer.

Need An Account,

1 Answer

  1. Editorial Team

    The IEEE standard requires that the result of addition, subtraction, multiplication and division be exactly rounded. The result must then be rounded to the nearest floating-point number. Floating point error is accumulated in the many operators it takes to normalize a vector.
    Like the other poster said FLT_EPSILON is too small.

    • 0