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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T21:13:13+00:00 2026-05-13T21:13:13+00:00

I noticed while making a program that a lot of my int type variables

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I noticed while making a program that a lot of my int type variables never went above ten. I figure that because an int is 2 bytes at the shortest (1 if you count char), so I should be able to store 4 unsigned ints with a max value of 15 in a short int, and I know I can access each one individually using >> and <<:

short unsigned int SLWD = 11434;
S is (SLWD >> 12), L is ((SLWD << 4) >> 12),
W is ((SLWD << 8) >> 12), and D is ((SLWD << 8) >> 12)

However, I have no idea how to encompase this in a function of class, since any type of GetVal() function would have to be of type int, which defeats the purpose of isolating the bits in the first place.

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  1. Editorial Team
    Editorial Team
    2026-05-13T21:13:14+00:00Added an answer on May 13, 2026 at 9:13 pm

    First, remember the Rules of Optimization. But this is possible in C or C++ using bitfields:

    struct mystruct {
        unsigned int smallint1 : 3; /* 3 bits wide, values  0 -- 7 */
        signed int   smallint2 : 4; /* 4 bits wide, values -8 -- 7 */
        unsigned int boolean   : 1; /* 1 bit  wide, values  0 -- 1 */
    };
    

    It’s worth noting that while you gain by not requiring so much storage, you lose because it becomes more costly to access everything, since each read or write now has a bunch of bit twiddling mechanics associated with it. Given that storage is cheap, it’s probably not worth it.

    Edit: You can also use vector<bool> to store 1-bit bools; but beware of it because it doesn’t act like a normal vector! In particular, it doesn’t provide iterators. It’s sufficiently different that it’s fair to say a vector<bool> is not actually a vector. Scott Meyers wrote very clearly on this topic in ‘Effective STL’.

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