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Home/ Questions/Q 6949033
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T13:54:04+00:00 2026-05-27T13:54:04+00:00

I once read the following Perl code involving iterations. for my $j (0 ..

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I once read the following Perl code involving iterations.

for my $j (0 .. $#{$dat[$Row]})
{
    $vectors{ $dat[$Row][$j] } = $j;
}

What does

$vectors{ $dat[$Row][$j] } 

stand for?
Is that equivalent to $vectors->$dat[$Row][$j] ?

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  1. Editorial Team
    Editorial Team
    2026-05-27T13:54:05+00:00Added an answer on May 27, 2026 at 1:54 pm
    what does $vectors{ $dat[$Row][$j] } stand for?
    

    $dat[$Row] is a reference to an array. $dat[$Row][$j] is apparently an element in that array. Whatever value is contained in it, becomes a hash key in %vectors, which gets the value $j.

    Is that equivalent $vectors->$dat[$Row][$j]
    

    No, that would be referring to the variable $vectors, not %vectors.

    A more readable way to write this might be:

    my $aref = $dat[$Row];   
    for my $index (keys @$aref) {
        my $key = $aref->[$index];
        $vectors{$key} = $index;
    }
    

    Which also exemplifies the use of ->, to dereference a reference.

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