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I only know what I know through my experience through Computer Architecture course. Little-endian stores the LSB on the right and MSB on the left and on Big-endian it’s vice versa.
That would mean a byte representation of 18 is 0001 0010 and on Big-endian it would be 0100 1000.
No, it is not like that, say you have
3,168,415,017as 32 bit unsigned number here is the Little Endian binary representation of it:While the Big Endian representation would flip the BYTES but not the BITS inside the bytes.
Note that the bytes are flipped but the order of bits inside of each remains the same.