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Home/ Questions/Q 6842015
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Editorial Team
  • 0
Editorial Team
Asked: May 27, 20262026-05-27T00:02:44+00:00 2026-05-27T00:02:44+00:00

I post my code here.(I add the jquery into my web page) var dataString

  • 0

I post my code here.(I add the jquery into my web page)

var dataString ='username='+ username + '&password=' + password; 
//alert (dataString);return false; 

$.ajax({ 
        type: "POST", 
        url: "http://hisencha.sinaapp.com/login.php", 
        data: dataString, 
        success: function(data) { 

          if(data=='success'){
            window.location.href='list.html';
          }
          else{
            alert(data);
          };
        } 
      }); 

above is part of javascript

here is php(demo)

<?php
if ($_POST['username']=='aaa' && $_POST['password']=='aaa')
{
  echo 'success';
}
else
{
  echo 'error';
}
?>

What can I do now?And how to fix the error about acrossing domain.

Thank you thank you!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T00:02:44+00:00Added an answer on May 27, 2026 at 12:02 am

    Yeah, you can use JSONP to do it. Here’s some sample jQuery:

     $.ajax({ 
         type: "POST", 
         url: "http://hisencha.sinaapp.com/login.php?callback=?", 
         data: dataString,
          dataType: 'JSONP',
         success: function(data) { 
    
           if(data=='success'){
             window.location.href='list.html';
           }
           else{
             alert(data);
           };
         } 
       });
    

    And PHP:

    <?php
    $response = array(
         'something' => 'something'
    );
    echo $_GET[['callback'].'('.json_encode($response).')';
    ?>
    
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