Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 338715
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 12, 20262026-05-12T10:27:19+00:00 2026-05-12T10:27:19+00:00

I ran an application on my machine and it ran fine; I then run

  • 0

I ran an application on my machine and it ran fine; I then run the apoplication on another machine but I’m getting a socket timeout isse connecting to the box even though Pinging works fine. Below is my socket connection Logic:

        private bool openConnection(out IPEndPoint connection_Point)
    {
        bool connected = false;
        connection_Point = new IPEndPoint(m_address, m_port);
        m_sock = new Socket(AddressFamily.InterNetwork, SocketType.Stream, ProtocolType.Tcp);
        m_sock.SetSocketOption(SocketOptionLevel.Socket, SocketOptionName.ReuseAddress, 1);
        try
        {
            m_sock.Connect(connection_Point);
            connected = true;
        }//end of try logic
        catch (SocketException err)
        {
            connected = false;
            connection_Point = null;
            MessageBox.Show("Socket Exception thrown: " + err);
        }

        return connected;
    }
  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-12T10:27:19+00:00Added an answer on May 12, 2026 at 10:27 am

    ping will only tell if the IP address responds to pings. To confirm that a TCP socket can be opened, try telnet on the listening port from the new machine. If telnet doesn’t connect, the likely culprits are firewall and/or IPSec.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

Well, A small idea of making an application ran through my mind. But this
We made a simple application and using GoogleAppEngineLauncher (GAEL) ran that locally. Then we
My development machine is a quad core system, but I just ran into (
In my flex application when I added a tabnavigator control and ran the application,
While developer a client side application I ran into an error that I believe
I'm in the process of building a WPF application and ran into an error
I ran dotTrace on my application (which is having some issues). IntPtr System.Windows.Forms.UnsafeNativeMethods.CallWindowProc(IntPtr, IntPtr,
I ran into this dilemma when working on an ASP.net web application using Web
I ran across this chunk of code (modified) in our application, and am confused
I ran across a very strange line of code in a legacy Perl application.

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.