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Home/ Questions/Q 948687
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T23:16:59+00:00 2026-05-15T23:16:59+00:00

I ran into a problem that I need to access to private field of

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I ran into a problem that I need to access to private field of a class. For example:

class MyClass 
{
    private string someString;

    public MyClass( string someStringValue )
    {
        someString = someStringValue;
    }
}

How can I get the value of someString outside MyClass ?

Update:

Sorry, I cannot use property here since the the actual production code is protected. I’m a QA/Dev, I need a way to get those private for writing User Acceptance Test. So I cannot change production code. Can you help?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-15T23:17:00+00:00Added an answer on May 15, 2026 at 11:17 pm

    As others have said, since the field is private you should not be trying to get it with normal code.
    The only time this is acceptable is during unit testing, and even then you need a good reason to do it (such as setting a private variable to null so that code in an exception block will be hit and can be tested).

    You could use something like the method below to get the field:

    /// <summary>
    /// Uses reflection to get the field value from an object.
    /// </summary>
    ///
    /// <param name="type">The instance type.</param>
    /// <param name="instance">The instance object.</param>
    /// <param name="fieldName">The field's name which is to be fetched.</param>
    ///
    /// <returns>The field value from the object.</returns>
    internal static object GetInstanceField(Type type, object instance, string fieldName)
    {
        BindingFlags bindFlags = BindingFlags.Instance | BindingFlags.Public | BindingFlags.NonPublic
            | BindingFlags.Static;
        FieldInfo field = type.GetField(fieldName, bindFlags);
        return field.GetValue(instance);
    }
    

    So you could call this like:

    string str = GetInstanceField(typeof(YourClass), instance, "someString") as string;
    

    Again, this should not be used in most cases.

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