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Home/ Questions/Q 6710913
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T08:04:40+00:00 2026-05-26T08:04:40+00:00

I ran into the following in some legacy C code: typedef struct _somestruct_ {

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I ran into the following in some legacy C code:

typedef struct _somestruct_ {
 /* .... */
} SomeStruct_t

static void do_one_thing(SomeStruct_t *pInput){
   /* Do some read-only stuff with pInput */   
}


static void do_many_thing(SomeStruct_t input){
   do_one_thing(&input);
}

Does C actually permit this, even though the thing will likely blow up if do_one_thing is actually modified to write to pInput?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T08:04:40+00:00Added an answer on May 26, 2026 at 8:04 am

    This is completely legal C code. The code do_one_thing(&input) is simply passing the address of a parameter to the function do_one_thing. There is nothing wrong with this.

    It’s not even an issue if do_one_thing writes to pInput. The address is valid and points to a mutable value. There is nothing wrong with doing an update. Consider

    typedef struct _somestruct_ {
     int field;
    } SomeStruct_t
    
    static void do_one_thing(SomeStruct_t *pInput){
      // Completely legal  
      pInput->field = 42;
    }
    
    static void do_many_thing(SomeStruct_t input){
      do_one_thing(&input);
    }
    
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