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Home/ Questions/Q 8882307
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T20:32:44+00:00 2026-06-14T20:32:44+00:00

I ran the following scripts which is considered as same, but the output is

  • 0

I ran the following scripts which is considered as same, but the output is completely different,
can anyone explain why?

I first imported the necessary modules:

from ctypes import *
import numpy as np 

Code1:

AOVoltage = np.linspace(-1, 1, 2200)
AOVoltage = AOVoltage.ctypes.data_as(POINTER(c_double))
print AOVoltage.contents

c_double(1.821347161578237e-284)

Code2:

a = np.linspace(-1, 1, 2200)
AOVoltage = a.ctypes.data_as(POINTER(c_double))
print AOVoltage.contents

c_double(-1.0)

Code3:

AOVoltage = (np.linspace(-1, 1, 2200)).ctypes.data_as(POINTER(c_double))
print AOVoltage.contents

c_double(1.821347161578237e-284)
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  1. Editorial Team
    Editorial Team
    2026-06-14T20:32:45+00:00Added an answer on June 14, 2026 at 8:32 pm

    For this to work, you need to retain a reference to the original numpy array to prevent it from being garbage collected. This is why #2 works, and #1 and #3 don’t (their behaviour is undefined).

    This is explained in the documentation:

    Be careful using the ctypes attribute – especially on temporary arrays or arrays constructed on the fly. For example, calling (a+b).ctypes.data_as(ctypes.c_void_p) returns a pointer to memory that is invalid because the array created as (a+b) is deallocated before the next Python statement. You can avoid this problem using either c=a+b or ct=(a+b).ctypes. In the latter case, ct will hold a reference to the array until ct is deleted or re-assigned.

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