Question

I randomly get a row from a mysql-database using php (ugly random, I know). I then want to update a specific field in the row that I get (using form or POST), but I can’t seem to get it to work. I have tried to create an alias for the specific ID to use in the form-post, but that failed.

$query_Recordset1 = "SELECT id, username, message, ttime, field1, field2 FROM table WHERE done = 0 ORDER BY RAND() LIMIT 1";

Then I want to update field1 if a specific submit-button is pressed, the important thing is that it writes to the random row (specific ID) that is fetched.

<?php      
 if($submit)
 {     mysql_select_db("database", $connection);
       $sql = "UPDATE table SET field1 = field1 +1 WHERE id = '???')";
       $result = mysql_query($sql);
 }
?>
<form method="post" action="">
<input type="submit" name="submit" value="submit">
</form>

Any takes on my problem? Thanks!

Answer 1

You are doing it right

$query_Recordset1 = "SELECT id, username, message, ttime, field1, field2 FROM table WHERE done = 0 ORDER BY RAND() LIMIT 1";
$query = mysql_query($query_Recordset1);
$result = mysql_result($query);
while($result = mysql_fetch_object($result)){
    $sql = "UPDATE table SET field1 = field1 +1 WHERE id = '".mysql_real_escape_string($result->id)."')";
    $new = mysql_query($sql);
}

That’s just an example.

In you example, you would probably want to create a hidden field that contains the id

<input type="hidden" value="<?php echo $result->id; ?>" />

Then on your receiving page

   mysql_select_db("database", $connection);
   $sql = "UPDATE table SET field1 = field1 +1 WHERE id = '".mysql_real_escape_string($_POST['id'])."')";
   $result = mysql_query($sql);