Question

I read following code from somewhere:

template<class T> class A {
    T a;
public:
    A(T x):a(x) {}
    operator T() const {return a;}   // what is point here?
};


int _tmain(int argc, _TCHAR* argv[])
{
    A<int> a = A<int>(5);
    int n = a;
    cout << n;
    return 0;
}

What does below line mean?

operator T() const {return a;}

Answer 1

operator T() const {return a;}

This is the typecast operator. It’ll implicitly convert the class instance to T. In the example code you’ve posted this conversion is being performed at the line

int n = a;