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Home/ Questions/Q 7692091
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T20:46:23+00:00 2026-05-31T20:46:23+00:00

I read my teacher’s code, but I don’t understand. Could anyone please tell me

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I read my teacher’s code, but I don’t understand. Could anyone please tell me the join here mean?

    AddTask ^task1 = gcnew AddTask();
AddTask ^task2 = gcnew AddTask();
AddTask ^task3 = gcnew AddTask();

// First Method
Thread ^thread1 = gcnew Thread ( gcnew ParameterizedThreadStart( task1, &AddTask::Add ) );
Thread ^thread2 = gcnew Thread ( gcnew ParameterizedThreadStart( task1, &AddTask::Add ) );
Thread ^thread3 = gcnew Thread ( gcnew ParameterizedThreadStart( task1, &AddTask::Add ) );

thread1->Start("First");
thread2->Start("Second");
thread3->Start("Third");

thread1->Join();
thread2->Join();
thread3->Join();
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  1. Editorial Team
    Editorial Team
    2026-05-31T20:46:24+00:00Added an answer on May 31, 2026 at 8:46 pm

    The Join function blocks the calling thread until a thread terminates, while continuing to perform standard COM and SendMessage pumping.

    http://msdn.microsoft.com/en-us/library/95hbf2ta.aspx
    
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