Home/ Questions/Q 8234983
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Asked: 2026-06-07T18:39:16+00:00

I read the Programming Perl by By Tom Christiansen, brian d foy, Larry Wall,

  • 0

I read the “Programming Perl” by By Tom Christiansen, brian d foy, Larry Wall, Jon Orwant. There is the following text which I failed to understand (the exact places which I do not understand are marked with bold):

What you really want to know is which operators supply which context
to their operands. As it happens, you can easily tell which ones
supply list context because they all have LIST in their syntactic
descriptions. Everything else supplies scalar context. Generally,
it’s quite intuitive. If necessary, you can force scalar context
onto an argument in the middle of a LIST by using the scalar
pseudofunction. Perl provides no way to force list context in context,
because anywhere you would want list context it’s already provided
by the LIST of some controlling function.

For convenience I would like to formulate the following questions:

  1. What does it mean LIST in the snippet?

  2. What is syntactic description? (seems to be a some sort of documentation)

  3. What does it mean the next text:

you can force scalar context
onto an argument in the middle of a LIST

Share

Leave an answer

You must login to add an answer.

Need An Account,

1 Answer

  1. Editorial Team

    It’s quite simple, like the text says. Take a look at perldoc -f print for example:

    print FILEHANDLE LIST
print FILEHANDLE
print LIST

    Like it says right there, print takes LIST arguments, meaning anything posted after print is in list context. It is the same for any function where the argument(s) are denoted as LIST.

    With the scalar function, you can override this list context, so that your argument is not evaluated in list context. For example, a file handle readline statement such as:

    my $line = <$fh>;

    Is evaluated in scalar context, because $line is a scalar. This means only one line is read and put into the variable. However, if you were to do:

    print <$fh>;

    The readline is in list context, which means all remaining lines in the file will be read. You can override this by putting the readline statement in scalar context:

    print scalar <$fh>;

    And then you will just read one line. To be more precise, you can enforce scalar context in the middle of a list:

    print @list, scalar <$fh>, @list2;

    Which presumably is what is referred to in that quote of yours.

    • 0