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Home/ Questions/Q 510743
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T07:08:41+00:00 2026-05-13T07:08:41+00:00

I read to get the length of array in C++, you do this: int

  • 0

I read to get the length of array in C++, you do this:

int arr[17];
int arrSize = sizeof(arr) / sizeof(int);

I tried to do the same for a string:
where I have

string * arr;
arr = new (nothrow) string [213561];

And then I do

arr[k] = "stuff";

where I loop through each index and put “stuff” in it.

Now I want the size of the array which should be 213561, what’s the correct way to do it and why is it so complex in C++?

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  1. Editorial Team
    Editorial Team
    2026-05-13T07:08:42+00:00Added an answer on May 13, 2026 at 7:08 am

    The correct way of doing this in C++ is to use a vector. That way you can either specify a size up-front, or resize it as you go.

    Specifying size up-front:

    using namespace std;
    vector<string> arr(213561);
    
    for (vector<string>::iterator p = arr.begin(); p != arr.end(); ++p)
    {
      *p = "abc";
    }
    

    Expanding the vector as you go:

    using namespace std;
    vector<string> arr;  // <-- note, default constructor
    
    for (int i = 0; i < 213561; ++i)
    {
      // add elements to the end of the array, automatically reallocating memory if necessary
      arr.push_back("abc");
    }
    

    Either way, the size of the array is found with:

    size_t elements = arr.size();  // = 213561
    
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