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Home/ Questions/Q 718239
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T05:30:14+00:00 2026-05-14T05:30:14+00:00

I read your reply regarding the jQuery validator where you outline a method to

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I read your reply regarding the jQuery validator where you outline a method to check a username against a value in a database.

Ive tried implementing this method but no matter what is returned from the PHP file I always get the message that the username is already taken.

Here is ths custom method…

$.validator.addMethod("uniqueUserName", function(value, element) {
  $.ajax({
      type: "POST",
       url: "php/get_save_status.php",
      data: "checkUsername="+value,
      dataType:"html",
   success: function(msg)
   {
      // if the user exists, it returns a string "true"
      if(msg == "true")
         return false;  // already exists
      return true;      // username is free to use
   }
 })}, "Username is Already Taken");

And here is the validate code…

username: {
    required: true,
    uniqueUserName: true
},

Is there a specific way i am supposed to return the message from php.

Thanks

A

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  1. Editorial Team
    Editorial Team
    2026-05-14T05:30:14+00:00Added an answer on May 14, 2026 at 5:30 am

    You are doing an AJAX request, ergo: the validation is already finished working when your custom validator returns either true or false.

    You will need to work with async. See also this post: How can I get jQuery to perform a synchronous, rather than asynchronous, Ajax request?

    Something like:

    function myValidator() {
       var isSuccess = false;
    
       $.ajax({ url: "", 
                data: {}, 
                async: false, 
                success: 
                    function(msg) { isSuccess = msg === "true" ? true : false }
              });
        return isSuccess;
    }
    

    Warning:

    As of jQuery 1.8, the use of async: false with jqXHR ($.Deferred) is
    deprecated; you must use the success/error/complete callback options
    instead of the corresponding methods of the jqXHR object such as
    jqXHR.done() or the deprecated jqXHR.success().

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