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Home/ Questions/Q 8852715
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T13:28:15+00:00 2026-06-14T13:28:15+00:00

I realise this is probably a simple question but what is ‘#::’ achieving in

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I realise this is probably a simple question but what is ‘#::’ achieving in below line of code. Is it a special variance of cons ?

def from(n: Int): Stream[Int] = n #:: from(n + 1)
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  1. Editorial Team
    Editorial Team
    2026-06-14T13:28:16+00:00Added an answer on June 14, 2026 at 1:28 pm

    This operator is used to construct streams as opposed to lists. Consider the same code snippet with simple cons:

    def from(n: Int): List[Int] = n :: from(n + 1)
    

    running this method will result in StackOverflowError. But with Stream[Int] tail is evaluated lazily only when it’s needed (and already computed values are remembered).

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