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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T23:56:52+00:00 2026-05-13T23:56:52+00:00

I realize that the method run() must be declared because its declared in the

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I realize that the method run() must be declared because its declared in the Runnable interface. But my question comes when this class runs how is the Thread object allowed if there is no import call to a particular package? how does runnable know anything about Thread or its methods? does the Runnable interface extend the Thread class? Obviously I don’t understand interfaces very well. thanks in advance.

    class PrimeFinder implements Runnable{
         public long target;
         public long prime;
         public boolean finished = false;
         public Thread runner;
         PrimeFinder(long inTarget){
              target = inTarget;
              if(runner == null){
              runner = new Thread(this);
              runner.start()
         }
    }
    public void run(){

    }
}
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  1. Editorial Team
    Editorial Team
    2026-05-13T23:56:52+00:00Added an answer on May 13, 2026 at 11:56 pm

    In this situation, I like to think of interfaces as contracts. By saying that your class implements Runnable, you are explicitly stating that your class adheres to the Runnable contract. This means that other code can create an instance of your class and assign to a Runnable type:

    Runnable r = new PrimeFinder();
    

    Further, by adhering to this contract you are guaranteeing that other code calling your class can expect to find the methods of Runnable implemented (in this case run() ).

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