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Home/ Questions/Q 6181613
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T01:03:27+00:00 2026-05-24T01:03:27+00:00

I really need help on this those function DATEDIFF OR DateAdd , because I

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I really need help on this those function DATEDIFF OR DateAdd , because I have no idea on those things.

Declare @EstDate as Date,
        @Shipdate as Date,
        @Workingday as Int,

I need to do like this:

@EstDate(Date) = @ShipDate(DATE) - @WorkingDay(int) - 2days

Example: @EstDate(date) = ‘6/11/2011’ – 5days – 2days.

How can I do this formula in SQL ? >_< In PHP its easy, but in SQL 2000 up, I have no ideas.

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  1. Editorial Team
    Editorial Team
    2026-05-24T01:03:27+00:00Added an answer on May 24, 2026 at 1:03 am

    I think this will do it. Basically this adds a negative number of days to @ShipDate. The negative number of days will equal @WorkingDay + 2.

    I really don’t know what @WorkingDay is supposed to represent. This example assumes it’s just a number that represents something to you.

    @EstDate = DateAdd(dd,-(@WorkingDay + 2),@ShipDate) 
    

    It would look something like this, given your example:

    @EstDate(date) = DateAdd(dd, -(5 days + 2 days), '6/11/2011')
    
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