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Home/ Questions/Q 8299277
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Editorial Team
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Editorial Team
Asked: June 8, 20262026-06-08T16:05:36+00:00 2026-06-08T16:05:36+00:00

I recently saw an example where the following was demonstrated to work: T Add<T>(dynamic

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I recently saw an example where the following was demonstrated to work:

T Add<T>(dynamic a, dynamic b)
{
    return a + b;
}

Add<string>("hello", "world");  // Returns "helloworld"

However, if I were to attempt to use expressions to create a “generic” Add function:

ParameterExpression left = Expression.Parameter(typeof(T), "left");
ParameterExpression right = Expression.Parameter(typeof(T), "right");
var add = Expression.Lambda<Func<T, T, T>>(Expression.Add(left, right), left, right).Compile();  // Fails with System.InvalidOperationException : The binary operator Add is not defined for the types 'System.String' and 'System.String' when T == String.

and then used this function with strings, it fails because the String type does not actually implement the + operator, but is simply syntactic sugar for String.Concat().

How then, does dynamic allow this to work? I figured that at runtime it is past the point where + would be rewritten using String.Concat().

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  1. Editorial Team
    Editorial Team
    2026-06-08T16:05:37+00:00Added an answer on June 8, 2026 at 4:05 pm

    dynamic uses runtime helper functions that replicate C# compiler rules. One of these rules allows + on string objects even when no operator is defined by the framework. The standard numeric types such as int have no custom operator overload either, that too is done by the compiler and needs to be performed at runtime when using dynamic. This is why you need a reference to Microsoft.CSharp.dll: dynamic cannot work without those helper functions.

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