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Home/ Questions/Q 769269
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T18:18:35+00:00 2026-05-14T18:18:35+00:00

I remember encountering this concept before, but can’t find it in Google now. If

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I remember encountering this concept before, but can’t find it in Google now.

If I have an object of type A, which directly embeds an object of type B:

class A {
    B b;
};

How can I have a smart pointer to B, e. g. boost::shared_ptr<B>, but use reference count of A? Assume an instance of A itself is heap-allocated I can safely get its shared count using, say, enable_shared_from_this.

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  1. Editorial Team
    Editorial Team
    2026-05-14T18:18:35+00:00Added an answer on May 14, 2026 at 6:18 pm

    D’oh!

    Found it right in shared_ptr documentation. It’s called aliasing (see section III of shared_ptr improvements for C++0x).

    I just needed to use a different constructor (or a corresponding reset function overload):

    template<class Y> shared_ptr( shared_ptr<Y> const & r, T * p );
    

    Which works like this (you need to construct shared_ptr to parent first):

    #include <boost/shared_ptr.hpp>
    #include <iostream>
    
    struct A {
        A() : i_(13) {}
        int i_;
    };
    
    struct B {
        A a_;
        ~B() { std::cout << "B deleted" << std::endl; }
    };
    
    int
    main() {
        boost::shared_ptr<A> a;
    
        {
            boost::shared_ptr<B> b(new B);
            a = boost::shared_ptr<A>(b, &b->a_);
            std::cout << "ref count = " << a.use_count() << std::endl;
        }
        std::cout << "ref count = " << a.use_count() << std::endl;
        std::cout << a->i_ << std::endl;
    }
    
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