Question

I require some help in reading and updating a csv file using Shell script. I have written the below code to read the csv file and it works fine.

#!/bin/sh
#This script is to read the excel data
IFS=","
echo "Starting to read csv"
i=1
while read f1 f2
do
    test $i -eq 1 && ((i=i+1)) && continue
    echo "tenantID is :$f1"
    echo "status is   :$f2"

#The below command will update the schema with data

java -Xmx512m -XX:MaxPermSize=128m -jar biz.jar -install -readers=seed -          delegator=default#$f1

done < TenantId.csv

echo "end of file "

The above code is working fine. I.e it reads the csv file and passes the tenantID to the java arg. Once the java processing is done, I would like to update the status(f2) with some values. Also in the above code,blank lines are also getting executed.I would like to know how to process only the lines where data is present. Please let me know how to acheive the same.

Thanks in Advance

Answer 1

while read f1 f2
do
    test $i -eq 1 && ((i=i+1)) && continue
    [ -z "$f1" ] && continue
    echo "tenantID is :$f1"
    echo "status is   :$f2"

    #The below command will update the schema with data

    java -Xmx512m -XX:MaxPermSize=128m -jar biz.jar -install -readers=seed -          delegator=default#$f1

    echo $f1, XXX >> TenantIdOut.csv
done < TenantId.csv

Added 2 lines of code:

1. If the f1 is null, continue – This is to skip blank lines.
2. Write the record f1 and new status to a new file , and outside the loop you can rename the input file with this new file.