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Home/ Questions/Q 7649305
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T10:55:55+00:00 2026-05-31T10:55:55+00:00

I retrieve data from my database as such: while($row = mysql_fetch_array($result)) { echo $row[‘uid’];

  • 0

I retrieve data from my database as such:

while($row = mysql_fetch_array($result))
{
    echo $row['uid'];
    echo $row['note'];
}

and I print it with ajax as such:

xmlhttp.onreadystatechange = function () {
      if (xmlhttp.readyState == 4 && xmlhttp.status == 200) {
          console.log(xmlhttp.responseText)
      }
   }

but the problem is that the uid and note its one string. For example:

"45 note goes here"

How can I print each row separately. Something like this:

xmlhttp.onreadystatechange = function () {
      if (xmlhttp.readyState == 4 && xmlhttp.status == 200) {
          console.log(  <?php echo json_encode($row['uid']); ?>  );
          console.log(  <?php echo json_encode($row['note']); ?>  );
      }
   }
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-31T10:55:56+00:00Added an answer on May 31, 2026 at 10:55 am

    You’re pretty much right. In your php script, return a json string, then in your javascript you can parse that string into a javascript object. So:

    $json = array();
    while($row = mysql_fetch_array($result))
    {
       $json['uid']=$row['uid'];
       $json['note']=$row['note'];
    }
    print json_encode($json);
    

    Then

    xmlhttp.onreadystatechange = function () {
      if (xmlhttp.readyState == 4 && xmlhttp.status == 200) {
          var jsontext = xmlhttp.responseText;
          var json = JSON.parse(jsontext);
          console.log(json.uid)
          console.log(json.note)
      }
    }
    
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