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Editorial Team
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Asked: 2026-05-14T03:18:25+00:00

I retrieved data from the log table in my database. Then I started finding

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I retrieved data from the log table in my database. Then I started finding unique users, comparing/sorting lists, etc.

In the end I got down to this.

stats = {'2010-03-19': {'date': '2010-03-19', 'unique_users': 312, 'queries': 1465}, '2010-03-18': {'date': '2010-03-18', 'unique_users': 329, 'queries': 1659}, '2010-03-17': {'date': '2010-03-17', 'unique_users': 379, 'queries': 1845}, '2010-03-16': {'date': '2010-03-16', 'unique_users': 434, 'queries': 2336}, '2010-03-15': {'date': '2010-03-15', 'unique_users': 390, 'queries': 2138}, '2010-03-14': {'date': '2010-03-14', 'unique_users': 460, 'queries': 2221}, '2010-03-13': {'date': '2010-03-13', 'unique_users': 507, 'queries': 2242}, '2010-03-12': {'date': '2010-03-12', 'unique_users': 629, 'queries': 3523}, '2010-03-11': {'date': '2010-03-11', 'unique_users': 811, 'queries': 4274}, '2010-03-10': {'date': '2010-03-10', 'unique_users': 171, 'queries': 1297}, '2010-03-26': {'date': '2010-03-26', 'unique_users': 299, 'queries': 1617}, '2010-03-27': {'date': '2010-03-27', 'unique_users': 323, 'queries': 1310}, '2010-03-24': {'date': '2010-03-24', 'unique_users': 352, 'queries': 2112}, '2010-03-25': {'date': '2010-03-25', 'unique_users': 330, 'queries': 1290}, '2010-03-22': {'date': '2010-03-22', 'unique_users': 329, 'queries': 1798}, '2010-03-23': {'date': '2010-03-23', 'unique_users': 329, 'queries': 1857}, '2010-03-20': {'date': '2010-03-20', 'unique_users': 368, 'queries': 1693}, '2010-03-21': {'date': '2010-03-21', 'unique_users': 329, 'queries': 1511}, '2010-03-29': {'date': '2010-03-29', 'unique_users': 325, 'queries': 1718}, '2010-03-28': {'date': '2010-03-28', 'unique_users': 340, 'queries': 1815}, '2010-03-30': {'date': '2010-03-30', 'unique_users': 329, 'queries': 1891}}

It’s not a big dictionary. But when I try to do one last thing…it craps out on me.

 for k, v in stats:
    mylist.append(v)

too many values to unpack

What the heck does that mean??? TOO MANY VALUES TO UNPACK.

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1 Answer

  1. Editorial Team

    If you only want the values you could just do:

    mylist = stats.values()

    If you need the key – value pair you should iterate the dict’s items:

    mylist = []
for k,v in stats.iteritems():
    mylist.append(v)

    In the code in your question you are just iterating over the dicts keys.

    Since you assign a single string (the key) to the tuple (k,v) it’s characters are instead iterated; it’s logical that this complete string cannot be unpacked’ into a (k,v) tuple unless in a situation where you would have a string with a length of exactly two. That explains the error message: you’re trying to unpack every single character of the string into only two placeholders (k and v).

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